Wednesday, October 17, 2012

Quotient Rule Algebra

Introduction to quotient rule in algebra:

The integer part is divided into the two integer is called as the quotient. The quotient is the theoretical branches of mathematics. The quotient is used to the sets, spaces, or algebraic structures of these elements. These elements are the some equivalence relation. Consequence of the division is the quotient. The quotient is classified into number of the times the divisor divide into the dividend.

Quotient Rule Algebra:

The quotient rule algebra is the technique of the decision the derivative purpose that is the quotient.

Production rule:

The quotient rule algebra is a process of sentence the derivative of a function which is the quotient of two further functions for which derivatives are present.

The quotient rule algebra points cannot be in the where the similar to the numerator or denominator is not differentiable

Multiplying two power of the same base is the production rule, we can insert the element.

Exercise 1:

`A^(a).A^(b)=A^(a+b)`

`11^(2).11^(3)=11.11.11.11.11`

`11^(2+3)=11^(5)`

Power rule:

The power rule means power to power, simply multiply the exponents.

Example:

`x^(ab)=x^(ab)`

`(5^(2))^(3)=5^(2.3)=5^(6)` 

Quotient rule:

The Quotient rule algebra can divide the two powers with the similar base by subtracting the exponents.

Example:

`x^(a)-:x^(b)=x^(a+b)`

x=0

`1^(5)-:1^(2)=(1.1.1.1.1)/(1.1)`

`1^(5-2)=1^(3)`

Zero rule:

Zero rules some non zero number is move up to the power of zero equivalent to 1.

Example:

x°=1

x`!=0`

Negative exponents:

This is the last rule of the quotient rule. Some the non zero of the element is move up to the negative power equal. Reciprocal is moved to the opposite positive power.

Example :

`11^(-2)=(1)/(11^(2))`

` = (1)/(121)`

Algebra is widely used in day to day activities watch out for my forthcoming posts on Addition Property of Equality Definition and How do you Simplify Expressions. I am sure they will be helpful.

Example Problems:

Problem 1:

`((x+3)-(x-2))/((x+3)^(2))`

Solution:

` = (x+3-x+2)/(x^(2)+6x+9)`

` = (5)/(x^(2)+6x+9)`

Problem 2:

`x^(2)-5x+6-:x-2`

Solution:

`= x^(2)-2x-3x+6`

`= x(x-2)-3(x-2)`

=  `((x-3)(x-2))/(x-2)`

`= (x-3)`

Differentiation of Function Using the Quotient Rule:

The following formula is the differential of function using the quotient rule,

D = `(f(x))/(g(x))=(g(x)f'(x)-f(x)g'(x))/{g(x)}^(2)`

Quotient rule algebra is represented by the formal rule for differentiating problems; the information is classified by another. In the calculus, the finding the value of the function is the quotient is the quotient rule algebra.

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