Showing posts with label how to do standard deviation. Show all posts
Showing posts with label how to do standard deviation. Show all posts

Monday, July 9, 2012

Formula for Standard Deviation


In Statistics, Standard Deviation is the measure of variability or spread of scores within a set of data. It is calculated as the root mean square deviation of the values from their arithmetic mean
Standard Deviation Equation or Formula for Standard Deviation

Standard Deviation
The given data with ‘n’ data values, there are two types of data:
1. Sample data (selection from a bigger population)
2. Population data (from a group of sample)
The standard deviation formula or the standard deviation equation is given as,
Population Standard Deviation, s = square root of [sigma(xi-x(bar))^2/(n)]
Sample Standard Deviation, s = square root of [sigma(xi-x(bar))^2/(n-1)]
[ s is the standard deviation, xi = all the data items of a sample data (i is 1 to n), x(bar) = mean of the sample data, n=number of data items]

How to do Standard Deviation:
To find the Standard Deviation the steps involved are:
• First we need to count the number of data items in the given sample, this gives us ‘n’
• The mean of the data is calculated, x(bar)
• Subtract the mean from each data item and square the difference, [(x-x(bar)]2 tabulate this values
• Find the sum of the above tabulated values, sigma [(x-x(bar))^2]
• Divide the sum with the number of data items (n); sigma [(x-x(bar))^2]/n
• Once all this done, find the square root; square root {sigma [(x-x(bar))^2]/n}
Using the formula square root of {sigma [(x-x(bar))^2]/n} gives us the standard deviation of the given sample data
Consider a sample data, 5, 8, 11, 13, 18, 7, 14, 12. Let us find the standard deviation of the given sample data using a Standard Deviation Chart
There are eight scores in the given sample data, so n=8
The mean =(5+8+11+13+18+7+14+12)/8= 88/8 = 11

Data Values (x)        [x-x(bar)]2
5         (-6)^2=36
8        (-3)^2=9
11   (0)^2=0
13 (2)^2=4
18 (7)^2=49
7 (-4)^2=16
14 (3)^2=9
12 (1)^2=1

Sigma  [x-x(bar)]^2= 36+9+0+4+49+16+9+1= 124

Sigma  [x-x(bar)]2/n = 124/8 = 15.5

Standard Deviation =Square root{ Sigma  [x-x(bar)]2/n} = square root {15.5} = 3.94
So, the standard deviation of the given sample data is 3.94

Standard Deviation Graph
The standard deviation is a statistic which tells us how the various samples or data items of a sample data are distributed around the mean in a set of data. In a normal distribution, the graph of the standard deviation is in the shape of a bell curve. When the samples are mostly together then the graph we get is a steep bell curve; which shows that the standard deviation is small. When the samples are spread apart then the bell curve we get is relatively flat; which shows that the standard deviation is relatively large.