Introduction To solving box and whisker plots practice:
Box-and-whisker diagram is also called as box plot or Whisker plot.
It is a suitable way of graphically give a picture of groups of numerical data with the help of their five-number summaries.
Box and Whisker plots are generally used in the display of statistical analyses of a group of numbers.
The five number summary is a different name for the visual illustration of the box and whisker plot.
The five number summary consist of:
1. The 2nd quartile.
2. The 1st quartile.
3. The 3rd quartile.
4. The Largest value in a data set.
5. The minimum value in a data set.
Diagram of Box and Wisker Plot :-
Now Lets see an example problem that helps you to understand the topic Solving box and whisker plots practice .
Solved Example Problem on Solving Box and Whisker Plots Practice
Solve and draw the box plot for the following set of numbers
35, 24, 53, 57, 14, 78, 95
Solution:-
To draw the box plot for the given set of the numbers we have to arrange the given set of numbers in increasing order.
35, 24, 53, 57, 14, 78, 95
A box plot is entirely based on medians. The basic step is to find the median of the given set of the numbers.
Practice Help Step 1:-
We can find the median of set of numbers by using the formula` (n+1)/2`
14, 24, 35, 53, 57, 78, 95
Here the numbers in the set is odd (n=7) so we use this formula.
`(n+1)/2 = (7+ 1) /2 `
By Solving the above step we get 4
So the number in the fourth position is the median.
Here the number is 53
So the median is 53.
Practice Help Step 2:-
The median of lower numbers is called as lower quartile. (1st quartile).
14, 24, 35
Here the numbers in the set is odd (n=3) so we use this formula.
`(n+1)/2 = (3+ 1) /2 `
By solving the above we get as 2
Medial of lower set of numbers is 2
So the lower quartile is 24
Practice Help Step 3:-
The median of upper numbers is called as lower quartile. (3rd quartile).
57, 78, 95
Here the numbers in the set is odd (n=3) so we use this formula.
`(n+1)/2 = (3+ 1) /2 ` By solving the above we get as 2
Medial of upper set of numbers is 78
So the upper quartile is 78
Practice Help Step 4:-
The sample maximum is the number with the largest value in the data set.
Here it is 95
The sample maximum is 95
Practice Help Step 5:-
The sample minimum is the number with the smallest value in the data set.Having problem with 9th class cbse question papers keep reading my upcoming posts, i will try to help you.
Here it is 14
The sample minimum is 14
The 5 Number Summary is
The solved box plot gives the following information
Median – 53
Lower Quartile -24
Upper Quartile - 78
The sample maximum - 95
The sample minimum - 14
Box-and-whisker diagram is also called as box plot or Whisker plot.
It is a suitable way of graphically give a picture of groups of numerical data with the help of their five-number summaries.
Box and Whisker plots are generally used in the display of statistical analyses of a group of numbers.
The five number summary is a different name for the visual illustration of the box and whisker plot.
The five number summary consist of:
1. The 2nd quartile.
2. The 1st quartile.
3. The 3rd quartile.
4. The Largest value in a data set.
5. The minimum value in a data set.
Diagram of Box and Wisker Plot :-
Now Lets see an example problem that helps you to understand the topic Solving box and whisker plots practice .
Solved Example Problem on Solving Box and Whisker Plots Practice
Solve and draw the box plot for the following set of numbers
35, 24, 53, 57, 14, 78, 95
Solution:-
To draw the box plot for the given set of the numbers we have to arrange the given set of numbers in increasing order.
35, 24, 53, 57, 14, 78, 95
A box plot is entirely based on medians. The basic step is to find the median of the given set of the numbers.
Practice Help Step 1:-
We can find the median of set of numbers by using the formula` (n+1)/2`
14, 24, 35, 53, 57, 78, 95
Here the numbers in the set is odd (n=7) so we use this formula.
`(n+1)/2 = (7+ 1) /2 `
By Solving the above step we get 4
So the number in the fourth position is the median.
Here the number is 53
So the median is 53.
Practice Help Step 2:-
The median of lower numbers is called as lower quartile. (1st quartile).
14, 24, 35
Here the numbers in the set is odd (n=3) so we use this formula.
`(n+1)/2 = (3+ 1) /2 `
By solving the above we get as 2
Medial of lower set of numbers is 2
So the lower quartile is 24
Practice Help Step 3:-
The median of upper numbers is called as lower quartile. (3rd quartile).
57, 78, 95
Here the numbers in the set is odd (n=3) so we use this formula.
`(n+1)/2 = (3+ 1) /2 ` By solving the above we get as 2
Medial of upper set of numbers is 78
So the upper quartile is 78
Practice Help Step 4:-
The sample maximum is the number with the largest value in the data set.
Here it is 95
The sample maximum is 95
Practice Help Step 5:-
The sample minimum is the number with the smallest value in the data set.Having problem with 9th class cbse question papers keep reading my upcoming posts, i will try to help you.
Here it is 14
The sample minimum is 14
The 5 Number Summary is
The solved box plot gives the following information
Median – 53
Lower Quartile -24
Upper Quartile - 78
The sample maximum - 95
The sample minimum - 14
