Introduction for solving a literal equation:
The literal equations are nothing but the equations where it can be called as the formulas for finding the recipes of the given equation variables. From a given formula, some other variables can be solved can be called as the literal equations. This can be applicable for many of the algebraic and geometric formulas. Now we are going to see about solving a literal equation.
About Solving a Literal Equation:
Now we are going to see solving a literal equations. The solving literal equations can be found for the thing which is additional information in that equation.
For example for solving a literal equation:
The area of triangle can be given as `1/2` * base * height
Generally this formula is used to find the area of the triangle. But from this we can find the base or the height,
Base = `(2 * area)/(height)`
Height = `(2 * area)/(base)`
The above two equations can be called as the literal equations.
Algebra is widely used in day to day activities watch out for my forthcoming posts on math algebra solver and factoring algebraic expressions. I am sure they will be helpful.
Problems for Solving a Literal Equation:
Example 1:
Find the base length of the given triangle where the area is about 15 cm2 and the height is about 5 cm.
Solution:
Now we can use the literal equation for the triangle as follows,
Base = `(2 * area)/(height)`
Base = `(2 * 15)/5`
Base = `30/5`
Base = 6 cm.
Example 2:
Solve the perimeter of the rectangle P = 2L +2W for W.
Solution:
Let us take the given equation
P = 2L +2W
Now take the L term to the left hand side we get as,
P – 2L = 2W
Now divide by 2 on either side of equal sign
` (P - (2 * L))/2 ` = W
Example 3:
Solve for the literal equation for the area of parallelogram where the area of parallelogram is 20 cm2 and the base of the parallelogram is about 10 cm. Determine the height of parallelogram.
Solution:
The literal equation or the formula for the parallelogram can be given as follows,
Area = Base * height
Height = `(area)/ (base)`
Height = `20/10`
Height = 2 cm.
The literal equations are nothing but the equations where it can be called as the formulas for finding the recipes of the given equation variables. From a given formula, some other variables can be solved can be called as the literal equations. This can be applicable for many of the algebraic and geometric formulas. Now we are going to see about solving a literal equation.
About Solving a Literal Equation:
Now we are going to see solving a literal equations. The solving literal equations can be found for the thing which is additional information in that equation.
For example for solving a literal equation:
The area of triangle can be given as `1/2` * base * height
Generally this formula is used to find the area of the triangle. But from this we can find the base or the height,
Base = `(2 * area)/(height)`
Height = `(2 * area)/(base)`
The above two equations can be called as the literal equations.
Algebra is widely used in day to day activities watch out for my forthcoming posts on math algebra solver and factoring algebraic expressions. I am sure they will be helpful.
Problems for Solving a Literal Equation:
Example 1:
Find the base length of the given triangle where the area is about 15 cm2 and the height is about 5 cm.
Solution:
Now we can use the literal equation for the triangle as follows,
Base = `(2 * area)/(height)`
Base = `(2 * 15)/5`
Base = `30/5`
Base = 6 cm.
Example 2:
Solve the perimeter of the rectangle P = 2L +2W for W.
Solution:
Let us take the given equation
P = 2L +2W
Now take the L term to the left hand side we get as,
P – 2L = 2W
Now divide by 2 on either side of equal sign
` (P - (2 * L))/2 ` = W
Example 3:
Solve for the literal equation for the area of parallelogram where the area of parallelogram is 20 cm2 and the base of the parallelogram is about 10 cm. Determine the height of parallelogram.
Solution:
The literal equation or the formula for the parallelogram can be given as follows,
Area = Base * height
Height = `(area)/ (base)`
Height = `20/10`
Height = 2 cm.
