Factorization Solve Online

Introduction :

Factorization solve online guides you to understand the rules of factorization. To understand factorization, factorization solve online gives ample of time to grasp the concept. You can any time access online content and solve your doubts. Through factorization solve online you can 'by heart' the rules of factorization. Factorization solve online not only makes you clear all doubts regarding the subject, but also makes easy to remember it.

I like to share this Factorization of Polynomials with you all through my article.

What are the factors of 42? The answer is the factors of 42 are 6 and 7. Can 6 and 7 be factorized further? We will say yes because 6 = 2 x 3.. So now we can write 42 = 7 x 3 x 2. Here, 7, 6, 3 and 2 are called the factors of 42 because they can be multiplied by one another to get 42.

Similarly, to find the factors of an algebraic expression, we shall write it as a product of two or more algebraic expressions.

For example,

X(Y  +  Z) = X * (Y + Z)     -> Here the product of X and (Y + Z) is X(Y  +  Z). So X and (Y  +  Z) are called the factors of X(Y  +  Z). But if X(Y  +  Z) is written as XY  +  XZ, then XY and XZ are not the factors of X(Y  +  Z), because we do not get X(Y  +  Z) on multiplying XY and XZ.


An example of solve factorization online


What are the factors of 30?                                                                                                                                                                                       30 = 3 x 10 = 3 x 5 x 2

Similarly, factors of 2XY are:

2XY = 1 and 2XY

2XY = 2 and XY

2XY = 2X and Y

2XY = X and 2Y

2XY = 2, X and Y

Therefore the factors of 2XY are 2, X, Y, 2X, 2Y, 1 and 2XY itself. This is the example of factors of a monomial.

Factorization of binomials:

15x²y³ + 12x³y

Here for the constant numbers 12 and 15, the common factor is 3, so we write the binomial as

3(5x²y³ + 4x³y)

and the common variables are x and y. The exponents of x are 2 and 3out of which take x²(the least value of the exponent) out. So we will write                                                                                                                                                                                                                              3(5x²y³ + 4x³y) as                                                                                                                                                                                                                   3x²(5y³ + 4xy)

Similarly, the exponents of y are 3 and 1. Take the least exponent out. Thus, the expressions becomes

3x²y (5y² + 4x)


Another factorization example (solve online)


Let us look at another example:

20 a²b³ + 32 a³b²

The common factor of 20 and 32 is 4.

So 4(5 a²b³ + 8 a³b²)

Now looking at the variables, the common variable 'a' has exponents 2 and 3, and the common variable b has exponents 3 and 2. As we did in the previous sum, take out the variables carrying the least exponents, that is b² and a², to get

4a²b²(5b + 4a)

This is a completely factorized expression.