Variable in Math Form

Introduction to variable in math form:

The varied values are denoted as variable using symbols in math form. It also represent the constant that is non varying value. The modern mathematics and engineering is use this variables for determine the unknown values. In math form, the variables are present in some theories. The variables are most commonly used in geometry and algebra.

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variables in function form


Function:

The functions are expressed by ideas with one or more variables. The variables function has ordered pairs. For example sum(a + b) = a  + b, here sum is denoted as function and a and b are variables of function. We can denote the function as f( x, y ). This is function of two variables.

Types of variables in math form:

A variable is varied based on problem and it is considered as characteristic of measurement. In math form different kinds of variables are used. They are quantitative and qualitative variables, independent and dependent variables.

Quantitative and qualitative variables in math form:

Quantitative variables are categorical data that is it denote the values of experiment. The ordinal, interval or ratio scale is measured by quantitative variables.

The qualitative variables are define the quality of math form and the nominal scale is used for measurement. For example favorite color, subjects are define the qualitative variables.

Independent and dependent variables:

The independent variables are also called as former variables and experiment is influence the independent variables in math form. The dependent variables are denoted as factors.

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More about math variables


Examples for variables:

Derive the math form  by using variables:

Problem 1: Find the unknown value  for the following math form:

X + 20 =10

Answer: This is simple example for variables.

X = 10 – 20

X = -10.

Problem 2: Find the values for following expressions:

2x + y = 4

X + y = 2

Answer:

2x + y =4 ----- (1)

X + y = 2 ------(2)

8x + 4y = 16 --- (1) x 4

4x + 4y = 8 -----(2) x 4

----------------

4x         = 8

X     = 8/4 = 2.

Sub x value in (1), 4 + y = 4

Y = 4 -4 =0

The x and y values are (2, 0).

Exercise problems in math form:

1. Find the value of y for 20 +y = 50.

Answer: y = 30.

2. Solve the following form and find the unknown value:

Answer:

60 + x = 75

X = 75 – 60

X = 15.

How to Understand Math

How to understand math (Introduction):
Math is also called as mathematics. Compare to other subject math is tough subject to understand this math subject; we want to listen the class care fully. Mathematics is separated into different sub titles shown here:

Number theory
Mensuration
Sets and functions
Algebra
Applied mathematics.
Geometry
Analytical geometry
Trigonometry
Practical geometry
Statistics
In this topic we discuss how to understand math with examples as problems are shown below:

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Easy Understand math Problems with Answers:


Problem 1:

Given the equation

5(-3x - 2) - (x - 3) = -4(4x + 5) + 13

Multiply factors.

-15x - 10 - x + 3 = -16x - 20 +13

Group like terms.

-16x - 7 = -16x - 7

Add 16x + 7 to both sides and write the equation as follows

0 = 0

Hence this statement is true for all values of x and therefore all real numbers are solutions to the given equation.

Problem 2:

Given the line

5x - 5y = 7

Re-write the equation in slope intercept form y = mx + b and identify the value of m the slope.

-5y = -5x + 7

y = x - ` 7/5`

The slope is given by the coefficient of x which is 1.

Problem 3:

To find the eqn of the line through the points (-1, -1) and (-1, 2), we use the slope m.

m = `(y_2 - y_1)/(x_2-x_1)` = `(2 - (-1)) / ((-1) - (-1))` = `3 / 0`

The slope is defined that means the line is perpendicular to the x axis and its equation has the form x = constant. Since all points have equal x coordinates with -1, the equation is given by:

x = -1

Problem 4:

Given the equation

2x - 4y = 10

To find the x intercept we set y = 0 and solve for x.

2x - 0 = 10

Solve for x.

x = `10 / 2`

= 5

The x intercept is at the point ( 5 , 0).

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Easy Understand math Practice Problems with Answers:


1. Find the statement is equal or not equal: 7(-4x - 3) - (x - 4) = -8(2x + 6) + 11

Answer: Not Equal.

2. To find the equation of the line through the points (-8, -6) and (-6, 2), we first use the slope m.

Answer: Slope m =1/4

3. Solve: 8x - 2y = 3

Answer:  The x intercept is at the point (3/8 , 0).

Math Work Problem Solver

Introduction :

Mathematics is the study of quantity, structure, space, and change. Mathematicians seek out patterns, formulate new conjectures, and establish truth by rigorous deduction from appropriately chosen axioms and definitions in this topic we are going to discuss about introduction of math problem solver with work, examples of math problem solver with work and practice math problems using solver with work (Source: Wikipedia).

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Math Work Problem Solver Example: 1


In a room there are 54 mans and 6 woman’s. The chief wants to select a man or women to represent the room in a function. In how many ways can the chief make this selection?

Solution:

Here the chief performs either of the following two jobs:

(i) Selecting a man among 54 mans. (or)

(ii) Selecting a woman among 6 woman’s

The first of these can be performed in 54 ways and the second in 6 ways.

Therefore, by fundamental principle of addition either of the two jobs can be performed in (54 + 6) = 60 ways

Hence, the chief can make the selection of either a man or a woman in 60 ways.


Math Work Problem Solver Example: 2


A room has 8 doors. In how many ways can a man enter the room through one door and come out through a different door?

Solution:

Clearly, a person can enter the room through any one of the eight doors. So, there are eight ways of entering into the room.

After entering into the room, the man can come out through any one of the remaining 7 doors. So, he can come out through a different door in 7 ways.

Hence, the number of ways in which a man can enter a room through one door and come out through a different door

= 8 × 7 = 56.


Math Work Practice Problem Solver:

1. A college has 15 doors. In how many ways can a man enter the room through one door and come out through a different door?

Answer: 210.

2. In a town there are 5000 mans and 4000 woman’s. The government staff wants to select a man or women to represent the room in a function. In how many ways can the govt staff make this selection?

Answer: 9000.

Online Algebra ii Test

Introduction :

An online algebra ii is also one kind of  mathematics . An online algebra ii explains the main properties of algebraical expressions and relations. This online algebra ii  explains the quantity, letters and other symbols. It indicates variables, equations, objects, polynomials, and expression etc. An online algebra ii, math test II solves lessons Pre-algebra, an online algebra I, an online algebra II, and Geometry. Fundamentally , Algebra involved from the properties and processes of arithmetic which begins with the four processes: addition, subtraction, multiplication and division of numbers.


Definition on online algebra ii test:


Numerals, some literal numbers are made by algebraical symbol. Which expression denotes one number or one quantity. That is, just like the sum of 4 and 2 is one quantity, which result is 6, The sum of X and Y is one quantity, that is, X + Y. Similarly divide b,√b , a*b, a – b are algebraic expressions each of these represents one quantity or one number. Some signs and mathematical symbols are used in the algebraic expression.

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Examples of online algebra ii test


Solve the online algebra ii test equations:
Example 1 on online algebra ii test:

Problem 1:

Solve the equation:

4(-2x - 1) - (x - 2) = -3(3x + 4) + 12

Solution to Problem 1:

Given the equation

4(-2x + 1) - (x + 2) = -3(3x + 4) + 6

Multiply factors.

-8x - 4 - x - 2 = -9x - 12 +6

Group like terms.

-9x - 6 = -9x - 6

Add 9x + 6 to both sides and write the equation as follows

0 = 0

For x value will be true for all statement x and therefore all real numbers are solutions to the given equation.

Simplify the expression 3(a -2) + 3b - 3(a -b -2) + 4

Problem 2:

Given the algebraic expression

3(a -2) + 3b - 3(a -b -4) + 4

Solution:

Multiply factors.

= 3a - 6 + 3b -3a + 3b + 12 + 4

Group like terms.

= 6b + 10.

Problem 3:

Simplify: 6c + 4d – 5d + 7c + d = 0

Solution:

Step 1: Group together the like terms:

6c + 4d – 5d + 7c + d = 0
(6c + 7c) + (4d – 5d +d) = 0

Step 2: Then simplify:

13c   = 0

Answer: 13c = 0.

Problem 4:

Simplify: 4(c – 3) + 2 = 7

Solution:

Step 1: Remove the brackets

4c – 12 + 2 = 7

Step 2: Isolate variable a

4c = 12 – 2 + 7
4c = 17
c=17/4 = 3.4

Answer: c = 3.4

Grade 8 Math Problems

Grade 8 Math Problems

Introduction to 8th grade math:

In this article you learned how to do 8th grade math. In 8th grade math covers the following topics:

Algebra
Linear algebra
Fraction
Quadratic equation
Algebraic expression
Area of triangle and parallelogram
Polynomial
Probability
In this content we discuss about the algebraic expression and quadratic equation with suitable example problems.


Example problems on 8th grade math:


Simplify the algebraic equation.

x^2 - x = 0

Solution:

Let us take the equation is
x^2 - x = 0

Take the common factor x outside
x (x - 1) = 0

So the product x (x - 1) to be equal to zero, then we get

x = 0 or x - 1 = 0

Solve the above simple equations to obtain the solutions.
x = 0
or
x = 1

Hence the answer is x=0 and x=1

Example problems on 8th grade math:

Solve x^2-15x-100

Solution:

Let P (x) = x^2-15x-100

Step 1: The given polynomial is in the form of ax^2+bx+c =0

a = 1; b =-15; c =-100

Multiply the coefficient of x^2 and the constant term,

1*-100 =-100 (product term)

Step 2: Find the factors for the product term

-100---- > -20*5 = -100 (factors 20 and -5)

-15 ---- >-20+5 =-15 (-15 is the coefficient of x)

Step 3: Divide the coefficient of x as -15

x^2-15x-100=0

x^2+5x-20x-100=0

Step 4: Taking the common term x from the first two terms and -20 from the next two terms

x(x+5) -20(x+5) =0

(x-20) (x+5) = 0.

Now set (x+5) =0; x=-5

(x-20) =0; x=20.

The roots are x=20 and -5.

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Example problems on 8th grade math:


Solve the algebraic expression

4(x -2) + 2y - 3(x -y -4) + 5

Solution:

Given algebraic expression is
4(x -2) + 2y - 3(x -y -4) + 5

Multiplying the integer with above terms

4x - 8 + 2y -3x -3y + 12 + 5

Combine like term
4x-3x +2y -3y -8+12+5

x –y +9

Hence the answer is x-y+9

Study Online Model

Introduction to study online model:

Nowadays, studies are getting more advanced and fast paced in change. One needs to keep up his/her level to the expected level in whichever stream of education chosen by him/her. Apart from learning in school, there are various ways to get help in homework, assignments, test preparations, etc. A study online model is a way of studying online. In it you get live help on any topic you need help with or on any thing related to it, like projects, homework, etc. Thus, you get a live session in which, like a teacher teaches in the class room, you get that at home and at any time you need help; the major advantage is that one gets the full attention of the tutor, as only one student and tutor are connected through a session. I like to share this Proportions in Math with you all through my article.


Benefits of study online model:


The concept of a 'study online model' helps us to understand the theory and to solve sums relating to the topic at our own pace and ease. This is because the advantage of a 'study online model' is that we get the chance to grasp a single concept at a time and thus divide the topic to be learnt into 'basic building blocks' according to our calibre. There is no time limit to cram up the subject and one can look back at any concepts any time which may need a bit of a revision during the course of study. There are ample of rich and versatile example questions along with their solutions to refer to. A study online model has an advantage that the online content has more scope of being 'accurate', or more properly, 'updated', owing to the high speed of change on the net. This also helps those students that lag behind in studies. You can always rework and rework any part of the subject not understood properly and thus clear away any trace of hesitation with the subject to be learnt.

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The increasing scope of studying online model


From the point of view of clashing of education and daily life, a study online model is the best type of gaining education as it gives us the most flexibility which one can expect during studying. One can study at any time during the day and night and get flash backs at any concept left over or not understood properly. Thus, the 'study online model' is one of the key educational models developed in the 21st century and will play a major role in the education of all – children or adults.

A study online model helps you to develop essential skills as a person given the opportunity to critically analyse his own level can effectively correct mistakes – and furthermore, if at any time any help is needed, it is there - 24 x 7.

Online Numeric Test

Introduction to online numeric test:

Online numeric test is the process of finding appropriate solutions to the problem displayed online.  The student needs to have a clear step by step approach to solve the problems presented online fast and accurate. This lesson deals with some sample problems for online tests. I like to share this Numerical Differentiation with you all through my article.


Math - online numeric test:

In online numeric test maths there are thousands of methods to find a solution for a problem by using different methods and various formulae. the most basic operations of study online calculating are given as below:

Addition,
Multiplication,
Subtraction and
Division
Steps to do online numeric test:
The basic steps of math solving from online numeric test are

At first, perform all the operations enclosed in the brackets

Then calculate the exponents

Next perform the multiplication and division operations

At last do the addition and subtraction.

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Online numeric test - Solved Examples:


Example 1: Solve the equation y +6 = 5.

Solution:

It is easy to solve within one step by grouping like terms

y = 5 - 6

y = -1

Example 2: Solve the equation 5y + 5= 25

Solution:

It is easy to solve within one step by grouping like terms

5y + 5 = 25

5y = 25 - 5

5y = 20

Divide by 5

y = 4

Example 3: Find the value: 25 y - 10 = 5 y - 5

Solution:

It is easy to solve within one step by grouping like terms

25y - 10 = 5y - 5

25y - 5y = 10 - 5

20 y = 5

Divide by 20

y = 1/4.

The answer is y = 1/4.

Example 4: Find the sum of 1000 + 5000?

Solution:

1000 + 5000 = 6000.

Answer = 6000.

Example 5: Solve the equation y +16 = 15.

Solution:

It is easy to solve within one step by grouping like terms

y = 15 - 16

solution :y = -1

Example 6: Solve the equation 5y + 15= 45

Solution:

It is easy to solve within one step by grouping like terms

5y + 15 = 45

5y = 45 - 15

5y = 30

Divide by 5

y = 6

Example 7: Find the value: 25 y - 15 = 15 y - 5

Solution:

It is easy to solve within one step by grouping like terms

25y - 15 = 15y - 5

25y - 15y = 15 - 5

5y = 10

Divide by 5

y = 1/2.

The answer is y = 1/2.